t^2-11t+21=0

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Solution for t^2-11t+21=0 equation: 



t^2-11t+21=0

a = 1; b = -11; c = +21;
Δ = b2-4ac
Δ = -112-4·1·21
Δ = 37
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{37}}{2*1}=\frac{11-\sqrt{37}}{2}
$


$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{37}}{2*1}=\frac{11+\sqrt{37}}{2}
$

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